2023 WikiGames - Collaborative Conifers Team Chat

+9 votes
234 views

Collaborative Conifers Image 1Hello and welcome to Team Collaborative Conifers! It's time to start thinking about the WikiGames!

We have three events
Sourcing Slalom starting Friday, August 25 at 8 am EDT/Noon UTC 
Cross Country Connecting on Saturday, August 26 at 8 am EDT/Noon UTC 
CC7x7 Wall Climb on Sunday, August 27 at 8 am EDT/Noon UTC.

*
Here is the full livecast schedule for the hangouts, every four hours: Space:WikiGames#LiveCast_Schedule

Come visit our Team Page at https://www.wikitree.com/wiki/Space:Collaborative_Conifers and let us know what you’ll be working on. Or you can start your own thread below by Answering this post. You can give us updates on your progress, ask for and give help, etc. Remember don't start on our 4 Olympians until the start of the CC7x7 wall climb on Sunday to maximize the gain. Nothing wrong with identifying potential connections beforehand though.

Please consider joining us on the Collaborative Conifers Discord Channel. It’s a lot of fun to have live conversations going on during these types of events. If you’re not already on the Discord server there are instructions on the help page.

I am looking forward to hanging out with you!

Eowyn ~ Team Cheerleader!

WikiTree profile: Space:Collaborative_Conifers
in The Tree House by Eowyn Walker G2G Astronaut (2.5m points)
reshown by Eowyn Walker

5 Answers

+10 votes
by Eowyn Walker G2G Astronaut (2.5m points)

I made a George Elwood Hunt Jr free space page.

+9 votes
by Eowyn Walker G2G Astronaut (2.5m points)

Made a free-space page -- see the discord chat for information. Free space page Thomas Martin

+9 votes

Olympian #3: John Emery (1932-2022)

by Eowyn Walker G2G Astronaut (2.5m points)

I made a John Emery free space page.

+9 votes
by Eowyn Walker G2G Astronaut (2.5m points)

I made a Frederick Anthony Wilding (Wilding-543) free space page

+8 votes
Do the other teams get different Olympians?
by Ruth Ogilvy G2G6 Mach 2 (29.2k points)
Yes, each team has four of their own.

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