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R. Sanborn

Honor Code Signatory
Signed 17 Sep 2023 | 12 contributions | 2 thank-yous

My tree and research are currently on Ancestry - happy to share. I’m researching my family roots mostly in New England, going back to the Great Migration. Among many names: Gilbert, Langevin, others from French Canada; Sanborn, Pike, Sargent, others from England; McGinnis from Ireland/Scotland; and Dutch Mooers roots. One branch of my family is in the Bahamas, and I’m especially interested in tracing those roots: Rae (Scotland and/or Southern Loyalist); Menendez (Spain), Yonge (SC & GA loyalist); Lockhart and Munro (Scotland; path unknown); Doyle (Ireland). In all branches, I’ve started looking for and documenting enslavement and enslaved people in New England, the Caribbean and south. Also my husband’s side: Stone/Finkelstein/Rogoff (Eastern European Jewish to NY) and Bockman (PA
R. Sanborn
Child of [father unknown] and [mother unknown]
[sibling(s) unknown]
[children unknown]
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Profile last modified | Created 21 Aug 2023
This page has been accessed 27 times.

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DNA Connections
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  • 100.00% X DNA 100.00% R. Sanborn: AncestryDNA, GEDmatch FD5562094 [compare], Ancestry member rsanbornstone
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Hello R

Thank you for signing the WikiTree Honor Code! We're happy to have you as a new Wiki Genealogist. Make sure to check out the Intro to WikiTree page to learn how to get involved: https://www.wikitree.com/wiki/Help:How_to_Use_WikiTree

Ruth ~ WikiTree Greeter

posted by Ruth Jowett
Hi R

Do you have any questions about our Honor Code? https://www.wikitree.com/wiki/Special:Honor_Code

I'm happy to help!

Ruth ~ volunteer WikiTree Greeter

posted by Ruth Jowett
No, thanks! Very straightforward. I've been doing this awhile, just haven't gotten around to setting up a profile on Wikitree. Thank you for offering this.
posted by R. Sanborn
Welcome to WikiTree!

If you have any questions about WikiTree, just click the option to reply to this message and let me know how I can help.

Rosalie ~ WikiTree Greeter

posted by Rosalie (Martin) Neve

S  >  Sanborn  >  R. Sanborn